(12x^2-4x-1)=0

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Solution for (12x^2-4x-1)=0 equation:


Simplifying
(12x2 + -4x + -1) = 0

Reorder the terms:
(-1 + -4x + 12x2) = 0

Remove parenthesis around (-1 + -4x + 12x2)
-1 + -4x + 12x2 = 0

Solving
-1 + -4x + 12x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-1 + -6x)(1 + -2x) = 0

Subproblem 1

Set the factor '(-1 + -6x)' equal to zero and attempt to solve: Simplifying -1 + -6x = 0 Solving -1 + -6x = 0 Move all terms containing x to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -6x = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -6x = 0 + 1 -6x = 0 + 1 Combine like terms: 0 + 1 = 1 -6x = 1 Divide each side by '-6'. x = -0.1666666667 Simplifying x = -0.1666666667

Subproblem 2

Set the factor '(1 + -2x)' equal to zero and attempt to solve: Simplifying 1 + -2x = 0 Solving 1 + -2x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -2x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -2x = 0 + -1 -2x = 0 + -1 Combine like terms: 0 + -1 = -1 -2x = -1 Divide each side by '-2'. x = 0.5 Simplifying x = 0.5

Solution

x = {-0.1666666667, 0.5}

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